Giải bài 2 trang 266 – Bài 54 - SGK môn Vật lý lớp 10 Nâng cao

$\begin{align} & d=1,0\text{ }\left( mm \right)={{10}^{-3}}\text{ m; h = 32,6 }\left( mm \right)\text{ = 32,6}\text{.1}{{\text{0}}^{-3}}\text{ }\left( m \right);\text{ }\rho \text{ = 1}{{\text{0}}^{3}}\text{ }\left( kg/{{m}^{3}} \right) \\ & \sigma =\dfrac{h\rho gd}{4}=\dfrac{32,{{6.10}^{-3}}{{.10}^{3}}.9,{{8.10}^{-3}}}{4}=0,08\text{ }\left( N/m \right) \\ \end{align}$