Giải bài 60, 61 trang 178 SGK giải tích nâng cao 12

60. Ta có:

$\int\limits_{1}^{5}{\dfrac{dx}{2x-1}=}\dfrac{1}{2}\ln \left| 2x-1 \right|\left| _{\begin{smallmatrix} \\ 1 \end{smallmatrix}}^{\begin{smallmatrix} 5 \\ \end{smallmatrix}} \right.=\dfrac{1}{2}\ln 9=\ln 3$

Vậy $c=3$.

Chọn (B).

61. Ta có:

$\int\limits_{0}^{2}{2{{e}^{2x}}dx}={{e}^{2x}}\left| _{\begin{smallmatrix} \\ 0 \end{smallmatrix}}^{\begin{smallmatrix} 2 \\ \end{smallmatrix}} \right.={{e}^{4}}-1$

Chọn (B).