Giải bài 6 trang 23 SGK Hóa học 12 nâng cao

(A):  $CH_3CH=O+HCN \rightarrow CH_3-CH(CN)-OH$

(B):  $CH_3-CH(OH)-CN+H_2O+H_3O^+\xrightarrow{{{t}^{o}}} CH_3-CH(OH)-COOH+NH_4^+$

(C):  $nCH_2=CH-COOH\xrightarrow{{xt,p,{t}^{o}}} (-CH_2-CH(COOH)-)_n$

(D):  $CH_3COCH_3+HCN \rightarrow CH_3-(OH)C(CN)-CH_3$

(E):  $CH_3-(OH)C(CN)-CH_3+H_3O^++H_2O\xrightarrow{{{t}^{o}}} CH_3-(OH)C(COOH)-CH_3+NH_4^+$

        $CH_3-(OH)C(COOH)-CH_3\xrightarrow{{H_2SO_4,{t}^{o}}} CH_2=C(COOH)-CH_3$

(F):  $CH_2=C(COOH)-CH_3\xrightarrow{{xt,p,{t}^{o}}} (-CH_2-(COOH)C(CH_3)-)_n$