Giải bài 7 trang 187 SGK Hóa học 11

$\begin{align} & \underset{tinh \, bột}{\mathop{{{\left( {{C}_{6}}{{H}_{10}}{{O}_{5}} \right)}_{n}}}}\,+n{{H}_{2}}O\xrightarrow[{{H}^{+}}]{{{t}^{o}}}\underset{glucozơ}{\mathop{n{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\, \\ & {{C}_{6}}{{H}_{12}}{{O}_{6}}\xrightarrow{enzim}2\,{{C}_{2}}{{H}_{5}}-OH+2C{{O}_{2}} \\ & {{n}_{etan ol}}=\frac{{{10}^{6}}.95.80.2n}{162n.100.100}=93,{{83.10}^{2}} \\ & {{m}_{etan ol}}=4316,{{05.10}^{2}}g \\ & {{V}_{ancol\,etylic}}=\frac{m}{D}=\frac{4316,{{05.10}^{2}}}{0,789}\approx 547l \\ \end{align}$