Giải bài 7 trang 100 - SGK môn Hóa học lớp 11 nâng cao

$\begin{aligned} & {{n}_{Mg}}=0,25\,mol;\,{{n}_{Si{{O}_{2}}}}=0,075\,mol \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2Mg+Si{{O}_{2}}\xrightarrow{{{t}^{0}}}2MgO+Si \\ & \text{pư:}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{0,15}\,\,\,\,\,\,\,\,\,\text{0,075}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{0,075} \\ & \text{sau pư:}\,\,\,\,\,\,\text{0,1}\,\,\,\,\,\,\,\,\,\,\,\,\text{0}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{0,075} \\ & \text{Si+2NaOH+}{{\text{H}}_{2}}O\to N{{a}_{2}}Si{{O}_{2}}+3{{H}_{2}}\uparrow \\ & {{n}_{{{H}_{2}}}}=2{{n}_{Si}}=0,15\,mol\Rightarrow {{V}_{\uparrow }}=3,36\,L \\ \end{aligned}$

Si tan được trong dung dịch kiềm đặc tạo khí $H_2$