Giải bài 5 trang 195 SGK Hóa học 11

$\begin{align} & a)\,2C{{H}_{4}}\xrightarrow{{{1500}^{o}}C}CH\equiv CH+3{{H}_{2}} \\ & CH\equiv CH+{{H}_{2}}\xrightarrow[PbC{{O}_{3}}]{Pd}C{{H}_{2}}=C{{H}_{2}} \\ & C{{H}_{2}}=C{{H}_{2}}+{{H}_{2}}O\xrightarrow{{{H}_{2}}S{{O}_{4}},{{t}^{o}}}{{C}_{2}}{{H}_{5}}-OH \\ & {{C}_{2}}{{H}_{5}}OH+{{O}_{2}}\xrightarrow{enzim}C{{H}_{3}}C\text{OOH+}{{\text{H}}_{2}}O \\ & b){{C}_{6}}{{H}_{6}}+B{{r}_{2}}\xrightarrow{Fe,{{t}^{o}}}{{C}_{6}}{{H}_{5}}Br+HBr \\ & {{C}_{6}}{{H}_{5}}Br+2NaO{{H}_{du}}\xrightarrow[p]{{{t}^{o}}}{{C}_{6}}{{H}_{5}}-ONa+NaBr+{{H}_{2}}O \\ & {{C}_{6}}{{H}_{5}}ONa+C{{O}_{2}}+{{H}_{2}}O\to {{C}_{6}}{{H}_{5}}-OH\downarrow +NaHC{{O}_{3}} \\ & {{C}_{6}}{{H}_{5}}-OH+3B{{r}_{2}}\xrightarrow{{{H}_{2}}S{{O}_{4d}}}{{C}_{6}}{{H}_{2}}B{{r}_{3}}OH\downarrow +3HBr \\ \end{align}$