Giải bài 3 trang 193 SGK Hóa học 11

\(\begin{align} & \underset{x\,mol}{\mathop{{{C}_{6}}{{H}_{5}}-OH}}\,+Na\to {{C}_{6}}{{H}_{5}}-ONa+\underset{\frac{x}{2}mol}{\mathop{\frac{1}{2}{{H}_{2}}}}\, \\ & \underset{y\,mol}{\mathop{{{C}_{2}}{{H}_{5}}-OH}}\,+Na\to {{C}_{2}}{{H}_{5}}-ONa+\underset{\frac{y}{2}mol}{\mathop{\frac{1}{2}{{H}_{2}}}}\, \\ & \left\{ \begin{aligned} & 94x+46y=14 \\ & \frac{x}{2}+\frac{y}{2}=\frac{2,24}{22,4} \\ \end{aligned} \right. \\ & \left\{ \begin{aligned} & x=0,1 \\ & y=0,1 \\ \end{aligned} \right. \\ & {{m}_{phenol}}=0,1.94=9,4g \\ \end{align} \)