Giải bài 3 trang 179 - SGK môn Hóa học lớp 11 nâng cao

$\begin{align} & a)\,CH\equiv C-C{{H}_{3}}+{{H}_{2}}\xrightarrow{Ni,{{t}^{0}}}C{{H}_{3}}-C{{H}_{2}}-C{{H}_{3}} \\ & b)\,CH\equiv C-C{{H}_{3}}+{{H}_{2}}\xrightarrow{Pd,PbC{{O}_{3}}}C{{H}_{2}}=CH-C{{H}_{3}} \\ & c)\,CH\equiv C-C{{H}_{3}}+B{{r}_{2}}\xrightarrow{CC{{l}_{4}},-{{20}^{0}}C}CHBr=CBr-C{{H}_{3}} \\ & d)\,CH\equiv C-C{{H}_{3}}+B{{r}_{2}}\xrightarrow{CC{{l}_{4}},{{20}^{0}}C}CHB{{r}_{2}}-CB{{r}_{2}}-C{{H}_{3}} \\ & e)\,CH\equiv C-C{{H}_{3}}+AgN{{O}_{3}}+N{{H}_{3}}\xrightarrow{CC{{l}_{4}},-{{20}^{0}}C}CAg\equiv C-C{{H}_{3}}+N{{H}_{4}}N{{O}_{3}} \\ & g)\,CH\equiv C-C{{H}_{3}}+HC{{l}_{d}}\to C{{H}_{3}}-CC{{l}_{2}}-C{{H}_{3}} \\ & h)\,CH\equiv C-C{{H}_{3}}+HOH\xrightarrow{H{{g}^{2+}},\,{{H}^{+}}}C{{H}_{3}}-CH(O)-C{{H}_{3}} \\ \end{align}$

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