Giải bài 6 trang 210 SGK Hóa học 11

a)

 \(\begin{align} & \underset{x\,mol}{\mathop{C{{H}_{3}}C{OO}H}}\,+NaOH\xrightarrow{{{t}^{o}}}C{{H}_{3}}C{OO}Na+{{H}_{2}}O \\ & \underset{y\,mol}{\mathop{HC{OO}H}}\,+NaOH\to HC{OO}Na+{{H}_{2}}O \\ & \left( {{H}^{+}}+O{{H}^{-}}\to {{H}_{2}}O \right) \\ \end{align} \)

b) 

\(\begin{aligned} & \left\{ \begin{aligned} & 60x+46y=16,6 \\ & 82x+68y=23,2 \\ \end{aligned} \right. \\ & \Rightarrow \left\{ \begin{aligned} & x=0,2 \\ & y=0,1 \\ \end{aligned} \right. \\ \end{aligned} \)

Trước phản ứng:

\(\%CH_3COOH=\frac{60.0,2.100}{16,6}=72,29\%\)

\(\%HCOOH=27,71\%\)

Sau phản ứng:

\(\%CH_3COONa=\frac{82.0,2.100}{23,2}=70,69\%\)

\(\%HCOONa=29,31\%\)