Giải bài 5 trang 213 SGK Hóa học 11

\(\begin{align} & C{{H}_{3}}-C\text{OO}H+AgN{{O}_{3}}\xcancel{\to } \\ & C{{H}_{3}}-CHO+2AgN{{O}_{3}}+3N{{H}_{3}}+{{H}_{2}}O\to C{{H}_{3}}C\text{OON}{{\text{H}}_{4}}+2Ag\downarrow +2N{{H}_{4}}N{{O}_{3}} \\ & C{{H}_{3}}C\text{OO}H+NaOH\to C{{H}_{3}}C\text{OO}HNa+{{H}_{2}}O \\ & {{n}_{Ag}}=\dfrac{21,6}{108}=0,2mol \\ & {{n}_{C{{H}_{3}}CHO}}=\dfrac{0,2}{2}=0,1mol \\ & {{m}_{C{{H}_{3}}CHO}}=0,1.44=4,4g \\ \end{align} \)

\(\%CH_3CHO=\frac{4,4.100}{10}=44\%\)

\(\%CH_3COOH=56\%\)

\(n_{CH_3COOH}=\frac{10-4,4}{60}=0,093mol\)

\(\begin{align} & {{n}_{NaOH}}=0,093mol \\ & {{V}_{\text{dd}\,NaOH}}=\frac{n}{{{C}_{M}}}=\frac{0,093}{0,2}=0,467l \\ \end{align} \)