Giải bài 10 trang 213 SGK Hóa học 11

\(\begin{align} & C{{H}_{3}}-C{{H}_{2}}OH+CuO\xrightarrow{{{t}^{o}}}C{{H}_{3}}-CHO+Cu+{{H}_{2}}O \\ & C{{H}_{3}}-CHO+2AgN{{O}_{3}}+3N{{H}_{3}}+{{H}_{2}}O\xrightarrow{{{t}^{o}}}C{{H}_{3}}C\text{OO}N{{H}_{4}}+2Ag\downarrow +2N{{H}_{4}}N{{O}_{3}} \\ & {{n}_{Ag}}=\frac{8,1}{108}=0,075mol \\ & {{n}_{etan ol\,tham\,gia}}=\frac{0,075}{2}=0,0375mol \\ & {{m}_{etan ol\,tham\,gia }}=46.0,0375=1,725g \\ \end{align} \)

\(\Rightarrow H=\frac{1,725.100}{3}=57,5\%\)