Giải bài 3 trang 147 SGK Hoá học 11

$\begin{align} & a)CH\equiv CH+{{H}_{2}}\xrightarrow[{{t}^{o}}]{Pd/PbC{{O}_{3}}}C{{H}_{2}}=C{{H}_{2}} \\ & C{{H}_{2}}=C{{H}_{2}}+C{{l}_{2}}\to \underset{\left| {} \right.}{\mathop{C{{H}_{2}}}}\,-\underset{\left| {} \right.}{\mathop{C{{H}_{2}}}}\, \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl\,\,\,\,\,\,\,\,\,\,\,\,Cl \\ & b)CH\equiv CH+HCl\xrightarrow[{{t}^{o}}]{HgC{{L}_{2}}}C{{H}_{2}}=\underset{\left| {} \right.}{\mathop{CH}}\, \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl \\ & C{{H}_{2}}=\underset{\left| {} \right.}{\mathop{CH}}\,+HCl\to C{{H}_{3}}-CHC{{l}_{2}} \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl \\ \end{align}$

$\begin{align} & c)CH\equiv CH+B{{r}_{2}}\to \underset{\left| {} \right.}{\mathop{CH}}\,=\underset{\left| {} \right.}{\mathop{CH}}\, \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,\,\,\,Br \\ & d)2CH\equiv CH\xrightarrow[{{450}^{o}}C]{CuCl,N{{H}_{4}}Cl}C{{H}_{2}}=CH-C\equiv CH \\ & C{{H}_{2}}=CH-C\equiv CH+{{H}_{2}}\xrightarrow[{{t}^{o}}]{Pd/PBC{{O}_{3}}}C{{H}_{2}}=CH-CH=C{{H}_{2}} \\ \end{align}$

$\begin{align} & e)\underset{\left| {} \right.}{\mathop{Br}}\, \\ & \,\,\,\,\,\,\underset{\left| {} \right.}{\mathop{C{{H}_{{}}}}}\,-\underset{\left| {} \right.}{\mathop{C{{H}_{2}}}}\, \\ & \,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,\,\,\,Br \\ & CH\equiv CH+HBr\to C{{H}_{2}}=\underset{\left| {} \right.}{\mathop{CH}}\, \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br \\ & C{{H}_{2}}=\underset{\left| {} \right.}{\mathop{C{{H}_{{}}}}}\,+B{{r}_{2}}\to \underset{\left| {} \right.}{\mathop{C{{H}_{2}}}}\,-\underset{\left| {} \right.}{\mathop{C{{H}_{{}}}}}\,-Br \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,\,\,\,\,Br \\ \end{align}$