Giải bài 2 trang 147 SGK Hoá học 11

\(\begin{align} & 2C{{H}_{4}}\xrightarrow[{}]{{{1500}^{o}}C}CH\equiv CH+3{{H}_{2}} \\ & 2CH\equiv CH\xrightarrow[{{450}^{o}}C]{CuCl,N{{H}_{4}}Cl}C{{H}_{2}}=CH-C\equiv CH \\ & C{{H}_{2}}=CH-C\equiv CH+{{H}_{2}}\xrightarrow[{{t}^{o}}]{Pd/PdC{{O}_{3}}}C{{H}_{2}}=CH-CH=C{{H}_{2}} \\ & nC{{H}_{2}}=CH-CH=C{{H}_{2}}\xrightarrow[{{t}^{o}},p]{Na}{{(-C{{H}_{2}}-CH=CH-C{{H}_{2}}-)}_{n}} \\ \end{align} \)