Giải bài 2 trang 135 SGK Hóa học 11

\(\begin{align} & a)\,C{{H}_{2}}=\underset{\left| {} \right.}{\mathop{C}}\,-CH=C{{H}_{2}}+2{{H}_{2}}\xrightarrow{{{t}^{o}},Ni}C{{H}_{3}}-\underset{\left| {} \right.}{\mathop{CH}}\,-C{{H}_{2}}-C{{H}_{3}} \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\ & b)\,C{{H}_{2}}=\underset{\left| {} \right.}{\mathop{C}}\,-CH=C{{H}_{2}}+\,B{{r}_{2\,(\text{dd})}}\to \underset{\left| {} \right.}{\mathop{C{{H}_{2}}}}\,-\underset{\left| {} \right.}{\mathop{C}}\,=CH-C{{H}_{2}}Br \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\underset{1\,mol}{\mathop{C{{H}_{3}}}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\underset{1\,mol}{\mathop{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,C{{H}_{3}} \\ & c)\,nC{{H}_{2}}=\underset{\left| {} \right.}{\mathop{C}}\,-CH=C{{H}_{2}}\xrightarrow{{{t}^{o}},xt,p}{{(-C{{H}_{2}}-\underset{\left| {} \right.}{\mathop{C}}\,=CH-C{{H}_{2}}-)}_{n}} \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\, \\ \end{align} \)