Giải bài 3 trang 115 SGK Hóa học 11

$\begin{align} & a)\,\underset{1\,mol}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{3}}}}\,+\underset{1\,mol}{\mathop{C{{l}_{2}}}}\,\xrightarrow{ánh\,sáng}C{{H}_{3}}-\underset{\left| {} \right.}{\mathop{CH}}\,-C{{H}_{3}}+HCl \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl \\ \end{align}$

$\begin{align} & b)\,C{{H}_{3}}-C{{H}_{2}}-C{{H}_{3}}\xrightarrow[xt]{{{t}^{o}}}C{{H}_{2}}=CH-C{{H}_{3}}+{{H}_{2}} \\ & c)\,{{C}_{6}}{{H}_{14}}+\frac{19}{2}{{O}_{2}}\xrightarrow{{{t}^{o}}}6C{{O}_{2}}+7{{H}_{2}}O \\ \end{align}$